Point P on the curve, x = 2tan ( y+ π/12), has a y-coordinate of π/4. Find an equation for the normal to the curve at P. Step 1 - Firstly, …

The curve C has equation y = 2x^2 - 12x + 16 Find the gradient of the curve at the point P (5, 6). The most simple way to find the …

Point P has x-coordinate 4, to work out the y-coordinate you should substitute x=4 into the equation of the circle. This gives you 16 + …

The point P has coordinates (3, 4) The point Q has coordinates (a, b) A line perpendicular to PQ is given by the equation 3x + 2y = 7 …

The curve C has equation y= (2x-3)^5, the point P lies on C and has coordinates (w, – 32), find (a) the value of w and (b) the …

To find the x coordinate of point P, we simply substitute in the value of y at P into the equation of the curve and solve for x = 4pi^2. (ii) …

The point P has coordinates (3,4). The Point Q has the coordinates (a,b). A line perpendicular to PQ is given by the equation …

The point P has coordinates (3,4), Q has the coordinates (a,b), a line perpendicular to PQ is given by the equation 3x+2y=7. Find an …