\$\begingroup\$ Though to build that from NAND/NOR gates would take four gates in total. It can be done with just three gates. Notice that the \$(AB)\$ is a 2-input AND gate, which is equivalent to \$\overline{\overline{AB}}\$ which is a 2-in NAND gate followed by an inverter (another 2-in NAND with both inputs tied together).

Nov 2, 2011 · You would have to make your three input NAND gate into a two input NAND gate by doing the following: Then you can write the VHDL using only two inputs and it won't be illegal. If you want to write complex NAND logic, you can add a process to your architecture and then use variables to capture sub parts of your logic and then apply NAND to those ...

Here are the 3-input logic ICs I am aware of: triple 3-input NAND 74HCT10, CD4023 triple 3-input NOR 74HCT27, CD4025 triple 3-input OR 74HCT4075, CD4075 triple 3-input AND 74HCT11, CD4073 There were the same types of 4-input gates made, now with two circuits per package.

Feb 28, 2020 · I really need help because I need to come up with a circuit with 3 inputs (input A, input B and input C) and a truth table where in every case except for when input A and input C are 1 the output is 1. So basically if input A and input C are both 1, the output is 0. In all the other cases, the output is 1.

Apr 3, 2020 · (a) With the bottom transistor on you'll get a potential divider between R3 and R4 of about 1/3 through the base-emitter junction of Q3 so Y1 would be about 5/3 V = 1.66. With the transistor B-E junction the simulation shows that the actual output voltage would be 1.44 V. This messes up your LOW signal.

Oct 21, 2021 · For AND and NAND gates, the situation is that any low input will fix the output to some state, regardless of the state of the other inputs. So, for AND/NAND you must hold unused inputs high instead, to permit the other inputs to operate normally. Another way to approach the problem is by tying any two inputs together, to form a single input.

Sep 24, 2014 · I'm trying to understand this because my homework asks me to take a circuit and convert it using NOR synthesis to only use nor gates, and I know how to do it with 2 input gates, but the gate with 3 inputs is throwing me for a spin.

Aug 17, 2021 · I learned that Boolean Expression for a 3-input Logic NAND Gate is , and is read as "A AND B AND C gives NOT Q". I am wondering why it's not read as "NOT (A AND B AND C) gives Q" as this seems to me aligns with the Boolean Expression more.

Jan 19, 2017 · i finally figured out that i had to add one more nand gate(red circle) to get the same truth table of a 3-input OR.The problem was that by not having one more nand there,i had (x' * y')' which equals to x+y.I should have (x+y)' so with the extra nand i get it.Thanks for every comment!

Jun 29, 2019 · How many transistors are there in a logic gate? If anybody asks me, I tell them: A NOT gate is 1 transistor. A NAND gate is 1 transistor per input. A NOR gate is 1 transistor per input. An AND gate is basically a NAND gate + a NOT gate, so it takes 1 transistor more than a NAND gate. Same for OR vs NOR.