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  1. By division algorithm, Dividend = (Divisor × Quotient) + Remainder. Using this, p (x) = (x - a) · q (x) + r. Substitute x = a p (a) = (a - a) · q (a) + r p (a) = (0) · q (a) + r p (a) = r i.e. the remainder = p (a). Hence, proved.
    www.cuemath.com/algebra/remainder-theorem/
    Proof Substituting the value x = a in f (x) = (x – a) × q (x) + r (x), we get f (a) = (a – a) × q (a) + r (a) ⇒ f (a) = 0 × q (a) + r (a) ⇒ f (a) = r (a) Here, the degree of the remainder is one less than the divisor polynomial’s degree. Based on the theorem, the remainder is always constant (degree 0) as we divide f (x) by a linear polynomial.
    mathmonks.com/remainder-theorem
    Remainder Theorem Proof For any polynomial g (x) the remainder theorem can easily be proved as, Let g (x) be a polynomial with a degree of 1 or greater than 1. Suppose that when g (x) is divided by (x – b), the quotient is q (x) and the remainder is r (x), i.e. g (x) = (x &#x2013 b) q (x) + r (x)
    www.geeksforgeeks.org/remainder-theorem/
     
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