Chebyshev's Theorem is a general result that applies to most discrete random variables (and most continuous probability distributions as well). I was watching videos and other people talking about this theorem and they say this theorem applies to any data set or distribution .

Chebyshev’s Theorem If $\mu$ and $\sigma$ are the mean and the standard deviation of a random variable X, then for any positive constant k the probability is at least $1- \frac{1}{k^2}$ that X will take on a value within k standard deviations of the mean; symbolically

Aug 25, 2018 · I need some help finding the standard deviation using Chebyshev's theorem. Here's the problem: You have concluded that at least $77.66\%$ of the $3,075$ runners took between $60.5$ and $87.5$ minutes to complete the $10$ km race. What was the standard deviation of these $3,075$ runners? I set up the formula as follows: $$.7766 = 1 - \frac{1}{k^2}$$

Jan 12, 2011 · According to Chebyshev's theorem, how many standard deviations from the mean would make up the central 60% of scores for this class? [What are the corresponding grades? Answer the same questions for central 80%. Do these values capture more than the desired amount? Does this agree with Chebyshev's theorem?]

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Oct 7, 2014 · In the book Proofs from The Book by Aigner and Ziegler there is a proof of 'Chebyshev's Theorem' which ...

Proof of Chebyshev's theorem. Ask Question Asked 13 years, 3 months ago. Modified 13 years, 3 months ago.

Chebyshev's Theorem and probability? 0. How would I use Chebyshev's inequality for this problem? 6. Prove ...

In Piskunov's Calulus (P375 & P385) & Hardy's Integration of Functions of a Single Variable (P48) mention is made of Chebyshev's theorem on the integration of binomial differentials however no proof for the general case is offered. I'm wondering if anybody has a proof of this theorem in general & hopefully a few references in English that ...

I don't need to discuss them both. Nor do I want the answer. Just a hint where I messed up. Here is the question: According to Chebyshev's theorem, the proportion of values from a data set that is further than 1.5 standard deviations from the mean is at least: a.) 0.67 b.) 0.17 c.) 1.33 d.) 0.22 Now, I plugged in the 1.5 into the "k" formula.