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    How does the modulo (%) operator work on negative numbers in …

    • Assuming that a and b are either float and/or int values, finite (not math.inf, math.nan etc.) and that bis not zero.... The result c is the unique number with the sign of b, such that a - c is divisible by b and abs(… See more

    What If abs(a) < Abs(B)?

    A lot of people seem to think this is a special case, or for some reason have difficulty understanding what happens. But there is nothing special here. For example: consider -1 … See more

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    What About with B Equal to Zero?

    It will raise ZeroDivisionError, regardless of whether b is integer zero, floating-point positive zero, or floating-point negative zero. In particular, it will notresult in a NaN value.… See more

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    What About Special Float Values?

    As one might expect, nan and signed infinity values for a produce a nan result, as long as b is not zero (which overrides everything else). nan values for b result in nan as well… See more

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    What About Other types?

    It's up to the type. For example, the Decimal type overloads the operator so that the result takes the sign of the numerator, even though it functionally represents the same kind … See more

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    Why Not Always Give A Positive Result, Or Take The Sign of A?

    The behaviour is motivated by integer division. While % happens to work with floating-point numbers, it's specifically designed to handle integer inputs, and the results for fl… See more

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