Jan 2, 2010 · Exponentiation in Java. As for integer exponentiation, unfortunately Java does not have such an operator. You can use double Math.pow(double, double) (casting the result to int if necessary). You can also use the traditional bit-shifting trick to compute some powers of two. That is, (1L << k) is two to the k-th power for k=0..63. See also

Feb 23, 2014 · [C:\java_code\]java MathXmpl 3.141592653589793 2.718281828459045 Since Math is in the java.lang package, it does not need to be imported. java.lang is the "default package" and everything in it is already implicitly imported for you.

Nov 1, 2011 · This is a pretty simple Java (though probably applicable to all programming) question: Math.random() returns a number between zero and one. If I want to return an integer between zero and hundred, I would do: (int) Math.floor(Math.random() * 101) Between one and hundred, I would do: (int) Math.ceil(Math.random() * 100)

Does Java have anything to represent infinity for every numerical data type? How is it implemented such that I can do mathematical operations with it? E.g. int myInf = infinity; //However it is done myInf + 5; //returns infinity myInf*(-1); //returns negative infinity I have tried using very large numbers, but I want a proper, easy solution.

Feb 4, 2010 · binomialCoefficient, in Commons Math Returns an exact representation of the Binomial Coefficient, "n choose k", the number of k-element subsets that can be selected from an n-element set. Share

Dec 29, 2009 · Note that it's Math.floor, because Math.round wouldn't be truncating. Oh, and this returns a double, because that's what most functions in the Math class return (like Math.pow and Math.floor). Caveat: Doubles suck for accuracy. One of the BigDecimal solutions should be considered first.

Jun 29, 2016 · I've used Euclid's algorithm to find the greatest common divisor of two numbers; it can be iterated to obtain the GCD of a larger set of numbers.

The Math.Random class in Java is 0-based. So, if you write something like this: Random rand = new Random(); int x = rand.nextInt(10); x will be between 0-9 inclusive. So, given the following array of 25 items, the code to generate a random number between 0 (the base of the array) and array.length would be:

Dec 23, 2015 · Java Puzzlers: Traps, Pitfalls, and Corner Cases Book by Joshua Bloch and Neal Gafter. There is a briefly explanation how to check if number is odd. First try is something similar what @AseemYadav tried: public static boolean isOdd(int i) { return i % 2 == 1; } but as was mentioned in book:

Mar 5, 2014 · The Math.round method returns a long (or an int if you pass in a float), and Java's integer division is the culprit. Cast it back to a double, or use a double literal when dividing by 10. Either: double total = (double) Math.round((num / sum * 100) * 10) / 10; or. double total = Math.round((num / sum * 100) * 10) / 10.0; Then you should get. 27.3